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feat: Make maximum number of results and events configurable (#1110)

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This commit is contained in:
TwiN
2025-05-17 16:10:28 -04:00
committed by GitHub
parent c411b001eb
commit 04692d15ba
29 changed files with 231 additions and 161 deletions
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11
storage/store/memory/util.go
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@@ -2,7 +2,6 @@ package memory
import (
"github.com/TwiN/gatus/v5/config/endpoint"
"github.com/TwiN/gatus/v5/storage/store/common"
"github.com/TwiN/gatus/v5/storage/store/common/paging"
)
@@ -51,7 +50,7 @@ func getStartAndEndIndex(numberOfResults int, page, pageSize int) (int, int) {
// AddResult adds a Result to Status.Results and makes sure that there are
// no more than MaximumNumberOfResults results in the Results slice
func AddResult(ss *endpoint.Status, result *endpoint.Result) {
func AddResult(ss *endpoint.Status, result *endpoint.Result, maximumNumberOfResults, maximumNumberOfEvents int) {
if ss == nil {
return
}
@@ -59,11 +58,11 @@ func AddResult(ss *endpoint.Status, result *endpoint.Result) {
// Check if there's any change since the last result
if ss.Results[len(ss.Results)-1].Success != result.Success {
ss.Events = append(ss.Events, endpoint.NewEventFromResult(result))
if len(ss.Events) > common.MaximumNumberOfEvents {
if len(ss.Events) > maximumNumberOfEvents {
// Doing ss.Events[1:] would usually be sufficient, but in the case where for some reason, the slice has
// more than one extra element, we can get rid of all of them at once and thus returning the slice to a
// length of MaximumNumberOfEvents by using ss.Events[len(ss.Events)-MaximumNumberOfEvents:] instead
ss.Events = ss.Events[len(ss.Events)-common.MaximumNumberOfEvents:]
ss.Events = ss.Events[len(ss.Events)-maximumNumberOfEvents:]
}
}
} else {
@@ -71,11 +70,11 @@ func AddResult(ss *endpoint.Status, result *endpoint.Result) {
ss.Events = append(ss.Events, endpoint.NewEventFromResult(result))
}
ss.Results = append(ss.Results, result)
if len(ss.Results) > common.MaximumNumberOfResults {
if len(ss.Results) > maximumNumberOfResults {
// Doing ss.Results[1:] would usually be sufficient, but in the case where for some reason, the slice has more
// than one extra element, we can get rid of all of them at once and thus returning the slice to a length of
// MaximumNumberOfResults by using ss.Results[len(ss.Results)-MaximumNumberOfResults:] instead
ss.Results = ss.Results[len(ss.Results)-common.MaximumNumberOfResults:]
ss.Results = ss.Results[len(ss.Results)-maximumNumberOfResults:]
}
processUptimeAfterResult(ss.Uptime, result)
}